Added solution for AoC 2022/3, in python and in rust

Signed-off-by: TuDatTr <tuan-dat.tran@tudattr.dev>
main
TuDatTr 2022-12-03 13:59:13 +01:00
parent a5420b8c51
commit 04f18534bc
17 changed files with 816 additions and 6 deletions

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@ -5,4 +5,5 @@ edition = "2021"
[dependencies]
tracing = "0.1.0"
tracing = "0.1.0"
clap = {version = "4.0.22", features = ["derive"]}

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@ -2,6 +2,8 @@ use std::fs::File;
use std::io::{Read, Write};
use std::path::Path;
use tracing::{debug, info};
pub mod cli;
pub fn create_file(path: &Path, content: String) {
info!("Creating file");

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@ -61,6 +61,7 @@ dependencies = [
name = "common"
version = "0.1.0"
dependencies = [
"clap",
"tracing",
]

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@ -17,7 +17,7 @@ name = "calorie_counting"
path = "src/bin.rs"
[dependencies]
clap = {version = "4.0.22", features = ["derive"]}
tracing = "0.1"
tracing-subscriber = {version = "0.3.16", features = ["env-filter"]}
common = {path = "../common/"}
common = {path = "../common/"}
clap = {version = "4.0.22", features = ["derive"]}

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@ -1,10 +1,9 @@
use common::cli::Cli;
use calorie_counting_lib::{task_1a, task_1b};
use clap::Parser;
use tracing::{info, debug};
mod cli;
use crate::cli::Cli;
pub fn main() {
tracing_subscriber::fmt::init();
debug!("Running with DEBUG logging");

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@ -0,0 +1 @@
/input.txt

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@ -0,0 +1,9 @@
# Rucksack Reorganization
Created this solution first, since the implementation seemed fairly easy.
Turns out it was.
<sub> Could use some more list comprehensions though </sub>
## Usage
Expecting the `input.txt` in the same folder as the `main.py`
`python main.py`

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@ -0,0 +1,26 @@
def task3a():
sum = 0
for rucksack in open('input.txt', 'r').read().splitlines():
left = rucksack[:int(len(rucksack)/2)]
right= rucksack[int(len(rucksack)/2):]
common = [c for c in left if c in right][0]
priority = ord(common) - ord('a') + 1 if common.islower() else ord(common) - ord('A') + 27
# print(f"{common}: {priority}")
sum += priority
return sum
print(f'Task 3a: {task3a()}')
def task3b():
sum = 0
lines = open('input.txt', 'r').read().splitlines()
for rucksacks in [lines[n:n+3] for n in range(0, len(lines), 3)]:
common = [d for d in [c for c in rucksacks[0] if c in rucksacks[1]] if d in rucksacks[2]][0]
priority = ord(common) - ord('a') + 1 if common.islower() else ord(common) - ord('A') + 27
# print(f"{common}: {priority}")
sum += priority
return sum
print(f'Task 3b: {task3b()}')

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@ -0,0 +1,2 @@
/target
/input

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@ -0,0 +1,518 @@
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@ -0,0 +1,15 @@
# Calorie Counting
Implementation of [this task](./task.md).
This time I ran with this implementation second, since it seemed easier to quickly implement in Python.
Implementing it in Python first, allowed me to have a more organized approach to the task, given that I had already completed it once.
I may continue doing this going forward.
## Usage
`cargo run --release -- --input <Path to file with inputs>`
Alternative
```sh
cargo install --release .
rucksack_reorganization -i <Path to file with inputs>
```

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@ -0,0 +1,17 @@
use common::cli::Cli;
use common::read_file;
use rucksack_reorganization_lib::{task_3a, task_3b};
use tracing::debug;
use clap::Parser;
pub fn main() {
tracing_subscriber::fmt::init();
let args = Cli::parse();
debug!("Args: {:?}", args);
let content = read_file(&args.input).unwrap();
println!("Result (3a): {}", task_3a(&content));
println!("Result (3b): {}", task_3b(&content));
}

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use tracing::{info, debug};
use itertools::Itertools;
mod rucksack;
use crate::rucksack::Rucksack;
/// Gives a list of characters in `first` and `second`, that are in both strings
fn common_chars(first: &str, second: &str) -> Vec<char> {
// probably not very idiomatic, also I shouldnt use Vec<char> here, instead String
debug!("Comparing: {:10}, {:10}", first, second);
let result = first.chars().filter(|c| second.chars().find(|d| d == c).is_some()).collect::<Vec<char>>();
info!("Common Characters: {:?}", result);
result
}
/// Converts `input` to it's "priority" based on the tasks specifications
/// a-z -> 01-26 respectivly
/// A-Z -> 27-52 respectivly
fn priority_of(input: &char) -> u64 {
debug!("Priority of {}", input);
let base: u32 = 'a'.into();
let mut priority: u32 = input.to_ascii_lowercase() as u32 - base + 1;
if input.is_ascii_uppercase() {
priority += 26;
}
let result: u64 = priority.into();
debug!("Priority {}", &result);
result
}
/// Solution for 3a
pub fn task_3a (content: &str) -> u64 {
content.split('\n')
.map(|c| Rucksack::new(c))
.map(|c| priority_of(&common_chars(&c.compartments[0], &c.compartments[1])[0]))
.sum()
}
/// Solution for 3b
pub fn task_3b (content: &str) -> u64 {
let result: u64 = content.split('\n')
.map(|c| Rucksack::new(c))
.chunks(3).into_iter()
.map(|c| {
let group = c.map(|r| r.total_content()).collect_vec();
let common_badge_0_1: String = common_chars(&group[0], &group[1]).into_iter().collect();
let badge = common_chars(&common_badge_0_1, &group[2])[0];
priority_of(&badge)
}).sum();
result
}
#[cfg(test)]
mod tests {
use super::*;
use common::create_file;
const CONTENT: &str = "vJrwpWtwJgWrhcsFMMfFFhFp\njqHRNqRjqzjGDLGLrsFMfFZSrLrFZsSL\nPmmdzqPrVvPwwTWBwg\nwMqvLMZHhHMvwLHjbvcjnnSBnvTQFn\nttgJtRGJQctTZtZT\nCrZsJsPPZsGzwwsLwLmpwMDw";
#[test]
fn test_common_chars() {
let inputs: Vec<&str> = CONTENT.split('\n').collect();
let results: Vec<char> = inputs.iter().map(|r| {
let rucksack = Rucksack::new(r);
common_chars(&rucksack.compartments[0], &rucksack.compartments[1])[0]
}).collect();
let expected: Vec<char> = vec!('p', 'L', 'P', 'v', 't', 's');
assert_eq!(results, expected);
}
#[test]
fn test_priority_of() {
let inputs: Vec<char> = vec!('p', 'L', 'P', 'v', 't', 's');
let results: Vec<u64> = inputs.iter().map(|c| priority_of(c)).collect();
let expected: Vec<u64> = vec!(16, 38, 42, 22, 20, 19);
assert_eq!(results, expected);
}
#[test]
fn test_task_3a() {
let result = task_3a(CONTENT);
let expected = 157u64;
assert_eq!(result, expected);
}
#[test]
fn test_task_3b() {
let result = task_3b(CONTENT);
let expected = 70;
assert_eq!(result, expected);
}
}

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use tracing::{info, debug};
const COMPARTMENT_COUNT: usize = 2;
#[derive(Debug, Clone)]
pub struct Rucksack {
pub compartments: [String; COMPARTMENT_COUNT],
}
impl Rucksack {
/// Splits the `total_content` by half and puts it in their respective compartments
pub fn new(total_content: &str) -> Self {
debug!("Rucksack with {}", total_content);
let split_position = total_content.len()/2;
let (left, right) = total_content.split_at(split_position.into());
let content = [left.to_string(), right.to_string()];
debug!("Rucksack with {:?}", content);
Rucksack {
compartments: content,
}
}
/// Returns the content of the rucksack as a single String
pub fn total_content(&self) -> String {
info!("");
self.compartments.concat().to_string()
}
}

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# --- Day 3: Rucksack Reorganization ---
## --- Part One ---
One Elf has the important job of loading all of the rucksacks with supplies for the jungle journey. Unfortunately, that Elf didn't quite follow the packing instructions, and so a few items now need to be rearranged.
Each rucksack has two large compartments. All items of a given type are meant to go into exactly one of the two compartments. The Elf that did the packing failed to follow this rule for exactly one item type per rucksack.
The Elves have made a list of all of the items currently in each rucksack (your puzzle input), but they need your help finding the errors. Every item type is identified by a single lowercase or uppercase letter (that is, a and A refer to different types of items).
The list of items for each rucksack is given as characters all on a single line. A given rucksack always has the same number of items in each of its two compartments, so the first half of the characters represent items in the first compartment, while the second half of the characters represent items in the second compartment.
For example, suppose you have the following list of contents from six rucksacks:
```
vJrwpWtwJgWrhcsFMMfFFhFp
jqHRNqRjqzjGDLGLrsFMfFZSrLrFZsSL
PmmdzqPrVvPwwTWBwg
wMqvLMZHhHMvwLHjbvcjnnSBnvTQFn
ttgJtRGJQctTZtZT
CrZsJsPPZsGzwwsLwLmpwMDw
```
The first rucksack contains the items vJrwpWtwJgWrhcsFMMfFFhFp, which means its first compartment contains the items vJrwpWtwJgWr, while the second compartment contains the items hcsFMMfFFhFp. The only item type that appears in both compartments is lowercase p.
The second rucksack's compartments contain jqHRNqRjqzjGDLGL and rsFMfFZSrLrFZsSL. The only item type that appears in both compartments is uppercase L.
The third rucksack's compartments contain PmmdzqPrV and vPwwTWBwg; the only common item type is uppercase P.
The fourth rucksack's compartments only share item type v.
The fifth rucksack's compartments only share item type t.
The sixth rucksack's compartments only share item type s.
To help prioritize item rearrangement, every item type can be converted to a priority:
Lowercase item types a through z have priorities 1 through 26.
Uppercase item types A through Z have priorities 27 through 52.
In the above example, the priority of the item type that appears in both compartments of each rucksack is 16 (p), 38 (L), 42 (P), 22 (v), 20 (t), and 19 (s); the sum of these is 157.
Find the item type that appears in both compartments of each rucksack. What is the sum of the priorities of those item types?
## --- Part Two ---
As you finish identifying the misplaced items, the Elves come to you with another issue.
For safety, the Elves are divided into groups of three. Every Elf carries a badge that identifies their group. For efficiency, within each group of three Elves, the badge is the only item type carried by all three Elves. That is, if a group's badge is item type B, then all three Elves will have item type B somewhere in their rucksack, and at most two of the Elves will be carrying any other item type.
The problem is that someone forgot to put this year's updated authenticity sticker on the badges. All of the badges need to be pulled out of the rucksacks so the new authenticity stickers can be attached.
Additionally, nobody wrote down which item type corresponds to each group's badges. The only way to tell which item type is the right one is by finding the one item type that is common between all three Elves in each group.
Every set of three lines in your list corresponds to a single group, but each group can have a different badge item type. So, in the above example, the first group's rucksacks are the first three lines:
```
vJrwpWtwJgWrhcsFMMfFFhFp
jqHRNqRjqzjGDLGLrsFMfFZSrLrFZsSL
PmmdzqPrVvPwwTWBwg
```
And the second group's rucksacks are the next three lines:
```
wMqvLMZHhHMvwLHjbvcjnnSBnvTQFn
ttgJtRGJQctTZtZT
CrZsJsPPZsGzwwsLwLmpwMDw
```
In the first group, the only item type that appears in all three rucksacks is lowercase r; this must be their badges. In the second group, their badge item type must be Z.
Priorities for these items must still be found to organize the sticker attachment efforts: here, they are 18 (r) for the first group and 52 (Z) for the second group. The sum of these is 70.
Find the item type that corresponds to the badges of each three-Elf group. What is the sum of the priorities of those item types?